Answer:
The numbers are 23, 68 and 17.
Step-by-step explanation:
Given:
The sum of three numbers is 108.
The second number is 4 times the third.
The first number is 6 more than the third.
Now, to find the numbers.
Let the third number be [tex]x[/tex].
The second number be [tex]4x[/tex].
And the first number be [tex]6+x[/tex].
According to question:
[tex](6+x)+4x+x=108[/tex]
Now adding the variables we get:
⇒[tex]6+6x=108[/tex]
Subtracting both sides by 6 we get:
⇒[tex]6x=102[/tex]
Dividing both sides by 6 we get:
⇒[tex]x=17.[/tex]
Third number = [tex]17.[/tex]
Second number = [tex]4x=4\times 17=68.[/tex]
First number = [tex]6+x=6+17=23.[/tex]
Therefore, the numbers are 23, 68 and 17.
Answer:
First number: 13
Second number: 76
Third number: 19
Step-by-step explanation:
Hope it helps :)
