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A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, is given by

h(t) = −4.9t2 + 12t + 10.

How long does it take to reach maximum height? (Round your answer to three decimal places.)

Respuesta :

oresegunabisola

Answer:

1.225m

Step-by-step explanation:

Maximum height is reached at time t when the derivative of equation is 0

[tex]\frac{dh}{dt}  = - 9.8t + 12\\[/tex]

- 9.8t + 12 = 0

-9.8t = -12

Divide through by - 9.8

[tex]\frac{-9.8t}{- 9.8}  = \frac{-12}{-9.8}[/tex]

t = 1.225m to 3 decimal places

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