Answer:
2. k can be any real number.
4. No real number can satisfy the equation.
6. y = - 3
Step-by-step explanation:
2. 8 - 3(k + 2) = 2 - 3k
[tex]$ \implies 8 - 3k - 6 = 2 - 3k $[/tex]
[tex]$ \implies 2 = 2 $[/tex]
Any value of 'k' will solve the equation. That is, this equation has infinitely many solutions.
4. -7(a - 3) = 11 - 7a
[tex]$ \implies -7a + 21 = 11 - 7a $[/tex]
[tex]$ \implies 10 = 0 $[/tex] which is absurd. So, this equation has no solution.
6. 4(4y - 3) - (y - 5) = -52
[tex]$ \implies 16y - 12 - y + 5 = - 52 $[/tex]
[tex]$ \implies 15y = - 52 + 7 = -45 $[/tex]
[tex]$ \implies y = - 3 $[/tex]
This equation has a unique solution.
