Respuesta :
Answer:
final pressure is [tex]4.77 \times 10^5 \ Pa[/tex].
[tex]W=-1.05 \times 10^4 \ J[/tex].
[tex]\dfrac{T_2}{T_1}=1.59.[/tex] and gas is heated.
Explanation:
We know for mono atomic gas , [tex]\gamma=1.67[/tex].
We know for adiabatic process,
[tex]P_1V_1^\gamma=P_2V_2^\gamma[/tex].
Putting all values we get :
P_2=[tex]4.77 \times 10^5 \ Pa[/tex]
Therefore final pressure is [tex]4.77 \times 10^5 \ Pa[/tex].
Now,
Work Done for adiabatic process is , [tex]W= \dfrac{1}{\gamma-1}\times (P_1V_1-P_2V_2)[/tex].
Putting all given values we get:
[tex]W=-1.05 \times 10^4 \ J[/tex].
Now,
We know , [tex]T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}[/tex].
Putting all given values , we get.
[tex]\dfrac{T_2}{T_1}=1.59.[/tex].
SInce the ratio of temperature of final and initial temperature of gas is 1.59.
So, Final temperature is more.
Therefore, Gas is heated.
