Answer:
The factors are [tex] (x- \frac {\bf 1} {\bf 2}){\bf (x+4)}{\bf (x+1)} [/tex]
Step-by-step explanation:
Given that [tex]\frac{1}{2} ,-4, -1 [/tex] are the zeroes of the polynomial
Let the polynomial be [tex]P(x)[/tex]
For the polynomial [tex]P(x)[/tex], If r is a zero of [tex]P(x)[/tex] then [tex](x-r) [/tex] will be a factor of P(x).
If [tex](x-r)[/tex] is a factor of P(x) then r will be a zero of P(x).
From the given Zeroes we can write it in form of factors as below:
[tex]P(x) = (x- \frac{1}{2})(x-(-4))(x-(-1)) [/tex]
[tex]P(x) = (x- \frac{1}{2})(x+4)(x+1) [/tex]
