A large container holds 8 gallons of water. After 56 minutes the container only has 1 gallon of water left. At what rate is the water leaking. gal/min​

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Answer:

The rate at which water leaking is [tex]\frac{1}{8}[/tex] gal/min.

Step-by-step explanation:

Given:

A large container holds 8 gallons of water.

After 56 minutes the container only has 1 gallon of water left.

Now, to find at what rate is the water leaking.

So, water leaked from the container = 8 gallons - 1 gallon = 7 gallons.

Time taken for leakage = 56 minutes.

Now, to get the rate:

[tex]\frac{Gallons\ of\ water\ leaked}{Time\ taken\ for\ leakage}[/tex]

[tex]=\frac{7 gallons}{56 minutes}[/tex]

[tex]=\frac{1 gallon}{8 minutes}[/tex]

The rate = [tex]\frac{1}{8}[/tex] gal/min.

Therefore, the rate at which water is leaking is [tex]\frac{1}{8}[/tex] gal/min.