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The height h (in feet) above the water of a cliff diver is modeled by h=-16x^2+10x26, where t is the time (in seconds). How long is the diver in the air?

Respuesta :

MathPhys

Answer:

1.625 seconds

Step-by-step explanation:

h = -16t² + 10t + 26

0 = -16t² + 10t + 26

0 = 8t² − 5t − 13

0 = (t + 1) (8t − 13)

t = -1 or 1.625

t must be positive, so the diver is in the air for 1.625 seconds.

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