Answer:
Q' = 0.688 cm³/min
Explanation:
Given that initial flow rate
Q= 1.86 cm³/min
Lets final flow rate is Q' cm³/min
From Poiseuilles law for
[tex]Q=\dfrac{\Delta P\pi r^4}{8\eta L}[/tex] -------1
Where
ΔP=Pressure difference
L= Length
η=viscosity
r= Radius
Given that all other factor is same only viscosity become 2.7 η.
New viscosity, η'= 2.7 η
New discharge Q'
[tex]Q'=\dfrac{\Delta P\pi r^4}{8\eta' L}[/tex] ----2
Q' η' = Q η
Form 1 and 2 equation
Q' x 2.7 η = 1.86 x η
Q' = 0.688 cm³/min
