Answer:
The magnitude of each charge is [tex]2.82\times10^{-6}\ C[/tex]
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.
We need to calculate the magnitude of each charge
Using formula of force
[tex]F=\dfrac{kq^2}{r^2}[/tex]
Where, q = charge
r = separation
Put the value into the formula
[tex]20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}[/tex]
[tex]q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}[/tex]
[tex]q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}[/tex]
[tex]q=2.82\times10^{-6}\ C[/tex]
Hence, The magnitude of each charge is [tex]2.82\times10^{-6}\ C[/tex]
