Answer:
1) [tex]\lambda = 11\times 10^{-4} m[/tex]
2)[tex] 2.51\times 10^9 Pa[/tex]
Explanation:
Given data:
speed of sound v = 1540 m/s
frequency f = 1.40 MHz = 1.40 \times 10^6 Hz
density [tex]\rho = 1060 kg/m^3[/tex]
1) we know that
[tex]v = f\lambda[/tex]
[tex]\lambda = \frac[v}{f} = \frac{1540}{1.40\times 10^6}[/tex]
[tex]\lambda = 11\times 10^{-4} m[/tex]
2) we know that
[tex]v= \sqrt{\frac{modulus}{density}}[/tex]
[tex]v^2 = \frac{\gamma}{\rho}[/tex]
[tex]\gamma = v^2 \rho[/tex]
[tex]\gamma = 1540^2 \times 1060 = 2.51 \times 10^9 Pa[/tex]
