contestada

In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 500 nm. The diffraction patternis observed on a screen 10 m away. What is the spacing between successiveminima in the pattern.

Respuesta :

Answer:

[tex]0.1[/tex] m

Explanation:

[tex]d[/tex] = slit width = 0.1 mm = 0.1 x 10⁻³ m

[tex]\lambda[/tex] = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

[tex]D[/tex] = Distance of the screen = 10 m

[tex]w[/tex] = Spacing between successive minima

Spacing between successive minima is given as

[tex]w = \frac{2D\lambda }{d}[/tex]

Inserting the values given

[tex]w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}[/tex]

[tex]w = 0.1[/tex] m