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The distance between two telephone poles is 36 m. When a 1.99 kg bird lands on the telephone wire midway between the poles, the wire sags 0.118 m. The acceleration of gravity is 9.8 m/s 2 . How much tension in the wire does the bird produce? Ignore the weight of the wire. Answer in units of N.

Respuesta :

Answer:1501.86 N

Explanation:

Given

Distance between Poles=36 m

Mass of bird (m)=1.99 kg

wire sag =0.118 m

angle made by wire with horizontal is given by

[tex]tan\theta =\frac{0.118}{18}=0.0065[/tex]

[tex]\theta =0.372^{\circ}[/tex]

Let [tex]T_1 and\ T_2[/tex] be the tensions in the wires

On resolving

[tex]T_1\cos\theta =T_2\cos \theta [/tex]

thus [tex]T_1=T_2[/tex]

and [tex]2T_1\sin \theta =mg[/tex]

[tex]2\times T_1 \times sin(0.372)=1.99\times 9.8[/tex]

[tex]T_1=1501.86 N=T_2[/tex]

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