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Using the variable definitions​ above, compute the force exerted on a single​ leg, of a perfectly stationary​ platform, by waves moving at a velocity of 12 ​m/s. The waves are not accelerating at and the coefficients of drag and inertia are 0.73 and 0.34​, respectively. The cross sectional area of one leg is 879 msquared and the volume of a leg is 9813 mSuperscript nothingcubed. The density of the water is 1002 ​kg/mcubed. Compute the force exerted on the leg of the platform.

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Answer:

46292640.48 N

Explanation:

a = Accelration of the water = 0

A = Cross sectional area = [tex]879\ m^2[/tex]

[tex]\rho[/tex] = Density of water = [tex]1002\ kg/m^3[/tex]

u = Velocity of water = 12 m/s

V = Volume of body = [tex]9813\ m^3[/tex]

[tex]C_d[/tex] = Drag coefficient = 0.73

[tex]C_m[/tex] = Inertia coefficient = 0.34

[tex]F=\rho C_mVa+\frac{1}{2}\rho C_dAu^2\\\Rightarrow F=1002\times 0.34\times 9813\times 0+\frac{1}{2}\times 1002\times 0.73\times 879\times 12^2\\\Rightarrow F=46292640.48\ N[/tex]

The force exerted on the leg of the platform is 46292640.48 N

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