Two numbers shown below,
When [tex]x=-0.31[/tex] , [tex]y=-\frac{4}{0.31}=-12.9[/tex]
When [tex]x=-12.68[/tex], [tex]y=-\frac{4}{12.68} =-0.31[/tex]
System of equations :
Let us consider that one number is x and other number is y.
Given that, two numbers multiply to 4 and add to -13
[tex]x*y=4\\\\x+y=-13[/tex]
Substitute [tex]y=\frac{4}{x}[/tex] in second equation.
[tex]x+\frac{4}{x} =-13\\\\x^{2} +4=-13x\\\\x^{2} +13x+4=0\\\\x=\frac{-13 \pm \sqrt{13^{2}-16 } }{2} \\\\x=-0.31,x=-12.68[/tex]
When [tex]x=-0.31[/tex] , [tex]y=-\frac{4}{0.31}=-12.9[/tex]
When [tex]x=-12.68[/tex], [tex]y=-\frac{4}{12.68} =-0.31[/tex]
Learn more about the system of equation here:
https://brainly.com/question/13729904
