Answer:
[tex]Molarity_{NaOH}=0.02166\ M[/tex]
Explanation:
Moles of KHP :
Given, Mass of KHP = 0.1082 g
Molar mass of KHP = 204.22 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{0.1082\ g}{204.22\ g/mol}[/tex]
[tex]Moles= 5.2982\times 10^{-4}\ mol[/tex]
According to the reaction shown below:
KHP + NaOH ⇒ KNaP + H₂O
1 mole of KHP reacts with 1 mole of NaOH
So,
[tex]5.2982\times 10^{-4}\ mol[/tex] of KHP reacts with [tex]5.2982\times 10^{-4}\ mol[/tex] of NaOH
Moles of NaOH = [tex]5.2982\times 10^{-4}\ mol[/tex]
Volume = 24.46 mL = 0.02446 L ( 1 mL = 0.001 L)
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
[tex]Molarity_{NaOH}=\frac{5.2982\times 10^{-4}}{0.02446}[/tex]
[tex]Molarity_{NaOH}=0.02166\ M[/tex]
