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A person riding a unicycle is biking along a sidewalk. The person rides over a slight drop in the sidewalk that has a vertical displacement of 1 cm. If the combined mass of the bicycle and person is 50 kg, what are the values for the parallel spring-damper system in the bicycle for the person to experience motion that is critically damped?

Respuesta :

Answer:

K=49.99 KN/m

Explanation:

Given that

Displacement,d = 1 cm

m= 50 kg

Frequency of oscillation given as

[tex]\omega =\sqrt{\dfrac{g}{d}}[/tex]

[tex]\omega =\sqrt{\dfrac{10}{0.01}}[/tex]

ω = 31.62 rad/s

We know that

[tex]\omega^2 m=K[/tex]

Now by

31.62² x 50 =K

K=49991.2 N/m

K=49.99 KN/m

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