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In a game of darts, the dart thrower releases the dart directly at the center of the target (the "bull’s eye") with a speed of 13.0 m/s, and the dart strikes the wall, 0.23 m directly below the center of the target. How far from the wall, along the x-axis, was the dart released?

Respuesta :

Answer:2.81 m

Explanation:

Given

speed(u)=13 m/s

dart strikes 0.23 m below

i.e. vertical distance traveled by dart is 0.23 m

considering dart motion similar to Projectile

[tex]h=ut+\frac{at^2}{2}[/tex]

[tex]0.23=0+\frac{9.8t^2}{2}[/tex]

[tex]t=0.216 s[/tex]

Horizontal distance travel by dart =u\times t

[tex]=13\times 0.216=2.81 m[/tex]

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