Respuesta :
Answer:
[tex]\dfrac{K_2}{K_1}=\dfrac{4}{3}[/tex]
Explanation:
When an object strikes the ground, the potential energy of the rock gets converted to the kinetic energy.
A rock is dropped from a distance [tex]R_e[/tex] above the surface of the earth and is observed to have kinetic energy [tex]K_1[/tex] when it hits the ground.
For another rock, It is dropped from twice the height [tex]2R_e[/tex] above the earth’s surface and has kinetic energy [tex]K_2[/tex] when it hits.
For the first rock, [tex]K_1=GMm(\dfrac{1}{R_e}-\dfrac{1}{2R_e})=\dfrac{GMm}{2R_e}[/tex]..............(1)
For the second rock, [tex]K_2=GMm(\dfrac{1}{R_e}-\dfrac{1}{3R_e})=\dfrac{2GMm}{3R_e}[/tex]..............(2)
Dividing equation (2) by (1) we get :
[tex]\dfrac{K_2}{K_1}=\dfrac{4}{3}[/tex]
Hence, this is the required solution.
