Answer:
The answer to your question is: letter A
Explanation:
mass = 42.6 g
T1 = 0 °C
T2 = 100°C
(1) Melt the ice.
Q = m x l
Q = 42.6 x 80
Q = 3408 cal
(2) Heat the water.
Q = mCΔT
Q = (42.6)(1)(100 - 0)
Q = 4260 cal
(3) Boil the water to steam.)
Q = m x l
Q = 42.6 x 540
Q = 23004 cal
Total heat = Q = 3408 + 4260 + 23004
Q = 30672 cal
1 cal -------------------- 4.184 J
30672 cal -------------- x
x = (30672 x 4.184) / 1
x = 128331.65 J
x = 1.28 x 10⁵ J
