Answer: 0.00102%
Step-by-step explanation:
Given : Human body temperatures are normally distributed with a mean of [tex]\mu=98^{\circ}F[/tex]and a standard deviation of [tex]s=0.61^{\circ}F[/tex]
A hospital uses [tex]100.6^{\circ}F[/tex] as the lowest temperature considered to be a fever.
Let x be the random variable that represents the human body temperatures.
[tex]z=\dfrac{x-\mu}{s}[/tex]
For x= 100.6, [tex]z=\dfrac{100.6-98}{0.61}=4.26229508197\approx4.26[/tex]
Using normal distribution table for z-values for right-tailed area ,
P(x>100.6)=[tex]P(Z>4.26)=0.0000102=0.00102\%[/tex]
Hence, the required probability = 0.00102%