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Oxygen-16 (15.994915 amu) is synthesized in the sun by fusion of Carbon-12 (12.000000 amu) and Helium-4
(4.00260 amu). How much energy is released in this nuclear reaction?
3.82 x 10-18 kJ
X 10-15
1.20 x 101

Respuesta :

Neetoo

Answer:

1.142 × 10⁻¹⁵ kJ

Explanation:

Total mass of C-12 and He-4 = 12.00000 + 4.00260 = 16.00260 amu

mass of O-16 = 15.99495 amu

Difference in mass = 16.00260 - 15.99495 = 0.00765 amu

The difference in mass 0.00765 is converted into energy.

It is known that,

1 amu = 931.46 MeV

then,

0.00765 amu × 931.46 MeV /amu = 7.1257 Mev

In joule:

1.142 × 10⁻¹⁵ kJ

Because 1 MeV = 1.6 × 10⁻¹⁶ Kj

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