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What happens to a 8 L volume of gas as you move from a pressure of 3 atm to 4 atm? Use the correct gas laws to determine the new volume.

Respuesta :

Neetoo

Answer:

As the pressure is increased from 3 atm to 4 atm volume of gas is decreased from 8 litters to 6 litters.

Explanation:

Given data:

Volume = 8 L

Initial pressure = 3 atm

Final pressure = 4 atm

New volume = ?

Solution:

we will use Boyle's law to solve this problem.

"The volume of given amount of gas is inversely proportional to the applied pressure at constant temperature"

According to the Boyle's law,

P₁V₁ = P₂V₂

V₂ =  P₁V₁  /  P₂

V₂ = 3 atm × 8 L / 4 atm

V₂ =  24 atm. L / 4 atm

V₂ = 6 L.

So, as the pressure is increased from 3 atm to 4 atm volume of gas is decreased from 8 litters to 6 litters.

Answer:

The new volume is 6 L.

Explanation:

Boyle’s law states that,

For a given amount of a gas, Pressure is inversely proportional to its volume at constant temperature

Thus the expression is PV = constant (T and n are constant)

When there is a change in pressure and volume, we make use of the expression  

[tex]P_1V_1=P_2V_2[/tex] (T and n are constants)

Where [tex]P_1[/tex] and [tex]V_1[/tex] are the Initial pressure and volume and

[tex]P_2[/tex] and [tex]V_2[/tex] are the final pressure and volume

Inversely proportional means when one increases the other one decreases. That is as per Boyle’s law when Pressure increases the volume will decrease and vice versa.

Let us solve this problem now

[tex]P_1[/tex] = 3atm

[tex]P_2[/tex] = 4atm

[tex]V_1[/tex] = 8L

[tex]V_2[/tex] = ?

Plugging in the values  

[tex]P_1V_1=P_2V_2[/tex] (T and n are constants)

[tex]V_2=\frac {(P_1 V_1)}{P_2}=\frac {(3atm \times 8L)}{4atm}[/tex]  

= 6 L is the Answer

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