Sure. I'm not sure if I like the computer aided instruction.
[tex] \dfrac{\tan A}{\sec A} = \dfrac{ \sin A / \cos A }{1 / \cos A} = \dfrac{\sin A \cos A}{\cos A} = \sin A[/tex]
so in the first block they want sin A and in the second block sin A cos A
Show
[tex] \sec \theta \cot \theta \sin \theta =1[/tex]
Proof,
[tex] \sec \theta \cot \theta \sin \theta =\dfrac{1}{\cos \theta} \cdot \dfrac{\cos \theta}{\sin \theta} \cdot \sin \theta = 1[/tex]
Looks like the box is cos θ
