hope this help Answer:( x - 3i√2)(x + 3i√2)
solve x² + 18 = 0
x² = - 18 ⇒ x = ±√- 18 = ±3i√2
factors are ( x - (3i√2))(x - (-3i√2))
x² + 18 = (x - 3i√2)(x + 3i√2
Step-by-step explanation:
Answer:
[tex]x^{2}+36=(x-6i)(x+6i)[/tex]
Step-by-step explanation:
The given expression is
[tex]x^{2}+36[/tex]
It's understood that this expression is equal to zero
[tex]x^{2} +36=0[/tex]
Now, we isolate the variable and then apply a squared root to each side of the equation
[tex]x^{2}=-36\\x=\±\sqrt{-36}[/tex]
At this point, you'll find that the equation doesn't have solution in the real numbers, that is, all solutions are in the complex numbers. We need to add the imaginary number [tex]i=\sqrt{-1}[/tex] to continue
[tex]x=\±\sqrt{-36}\\x=\±\sqrt{36}i\\x=\±6i\\\\x_{1}=6i\\x_{2}=-6i[/tex]
Now, representing these solution as factors, we would have
[tex]x-6i=0\\x+6i=0[/tex]
Finally,
[tex]x^{2}+36=(x-6i)(x+6i)[/tex]
