Respuesta :
Answer:
A)The kinetic energy at a point A when a particle of .41 kg moves at a speed of 5.0 m/s is 5.125 J.
B)The speed at point B of the particle of .41 kg with Kinetic Energy 8.5 J is 6.44 m/s.
C)The total Work done by the particle is 3.375 J.
A)Explanation
From the given statements, we know
Mass (m) = 0.41 kg
Velocity = 5.0 m/s
As we know Kinetic Energy (KE) = [tex]\frac{1}{2} \text { mass } \times \text { velocity }^{2}[/tex]
Substituting the values in the above equation, we find
Kinetic Energy (KE) = [tex]\frac{1}{2} \text { mass } \times \text { velocity }^{2}[/tex]
[tex]\frac{1}{2} \times 0.41 \times 5^{2}[/tex]= 5.125 joule
(b) Explanation
From the given statements, we know
Mass (m) = 0.41 kg
Kinetic Energy (KE) = 8.5 J
As we know Kinetic Energy (KE) = [tex]\frac{1}{2} \text { mass } \times \text { velocity }^{2}[/tex]
Substituting the values in the above equation, we find
Kinetic Energy (KE) = [tex]\frac{1}{2} \times 0.41 \times \mathrm{v}^{2}[/tex] = 8.5 J
Or, [tex]v^2[/tex] = [tex]\frac{8.5 \times 2}{0.41}[/tex] = [tex]\frac{8.5 \times 2}{0.41}[/tex]
Or, v = [tex]\sqrt{\frac{17}{0.41}}[/tex]=6.439 m/s ~ 6.44 m/s
(c) Explanation
From the above given statements, we know
Kinetic Energy at A = 5.125 J
Kinetic Energy at B = 8.5 J
As we know
Work Done = Change in Kinetic Energy (ΔKE)
So, Work Done (WD) = Kinetic Energy at B - Kinetic Energy at A
WD = (8.5 – 5.125) J = 3.375 J
