20% calcium and 80% Bromine
Our compound is CaBr₂
Formula mass = 200 g
Relative atomic mass of Ca = 40.078
Relative atomic mass of Br = 79.904
Therefore;
% composition of Ca = (40.078/200) 100%
= 20.039
= 20 %
% composition of Br = (79.904×2)/200) 100%
= 79.904 %
= 80%
Therefore; the approximate % composition by mass of CaBr₂ is 20% calcium and 80% Bromine