Answer:
Explanation:
Hello,
Based on a typical rate law such as:
[tex]-r=kC_i[/tex]
And the rate constant defined by the Arrhenius equation:
[tex]k=Aexp(\frac{-Ea}{RT} )[/tex]
If the temperature in Kelvin is doubled, [tex]k[/tex] will remain roughly constant based on the following example in which arbitrary values are assigned for the frequency factor and the activation energy:
[tex]\frac{k_T2}{k_T1} =\frac{2exp(\frac{-80}{8.314*1000K} )}{2exp(\frac{-80}{8.314*500K} )} \\\\\frac{k_T2}{k_T1} =0.99[/tex]
It is seen that the ratio between constants is pretty close to 1 which implies that the reaction rate will remain roughly constant as well if the concentration does not change.
Best regards.
