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A charity organization is holding a food drive with a goal to collect at least 1,000 cans of food by the end of the month. It currently has 565 cans from donations and is having an event where 87 guests will attend and bring cans. Which solution set represents the number of cans each guest must bring to meet the goal?

Respuesta :

calculista

Answer:

The number of cans each guest must bring to reach the goal must be greater than or equal to 5.

Step-by-step explanation:

Let

x -----> the number of cans each guest must bring to meet the goal

we know that

The number of guests multiplied by the the number of cans each guest must bring to meet the goal plus the currently cans must be greater than or equal to 1,000 cans

so

The inequality that represent this problem is

[tex]565+87x \geq 1,000[/tex]

Solve for x

[tex]565+87x \geq 1,000[/tex]

Subtract 565 both sides

[tex]87x \geq 1,000-565[/tex]

[tex]87x \geq 435[/tex]

Divide by 87 both sides

[tex]x \geq 435/87[/tex]

[tex]x \geq 5[/tex]

therefore

The number of cans each guest must bring to reach the goal must be greater than or equal to 5.

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