Answer:
[tex]v_{y} = 227[/tex] m/s
Explanation:
Assumptions: 0° is true North, and 90° is east (along the x-axis).
To solve this problem we must use the expression:
[tex]v_{y} = v_{0}sin(\theta)[/tex]
Where [tex]v_{y}[/tex] is the velocity in the y-direction (East), [tex]v_{0}[/tex] is the total velocity in the direction which the aircraft is travelling, and [tex]\theta[/tex] is the direction the aircraft is travelling (angle from the y-axis).
Using the equation above, we obtain the y-component of velocity
[tex]v_{y} = (243)sin(69) = 226.86...[/tex] m/s which is rounded to 227 m/s (due to the number of significant figures in the question).
