Daredevil122 Daredevil122

14-10-2019
Mathematics

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write the equation of a line that is perpendicular to y=-3/2x-3 that passes through the point 6,7

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Аноним Аноним

14-10-2019

Answer:

y = 2/3x + 3.

Step-by-step explanation:

The slope of the line is -1 / -3/2 = 2/3 so using the point slope form of a line we get:

y - 7 = 2/3(x - 6)

y = 2/3x - 4 + 7

y = 2/3x + 3.

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