Answer:
The charge on sphere A and C is [tex]\frac{3q}{8} C[/tex]
Solution:
As per the question:
Charge on sphere A = q C
Now,
When sphere A with 'q' charge is brought in contact with B then conduction takes place and equal charges are distributed on both the spheres as:
[tex]\frac{q + q}{2} = \frac{q}{2}[/tex]
Charge on each A and B is [tex]\frac{q}{2}[/tex]
Now, after separating both the spheres, when sphere B with charge [tex]\frac{q}{2}[/tex] touches uncharged sphere C, again conduction occurs and the charge is distributed as:
[tex]\frac{\frac{q}{4} + \frac{q}{4}}{2} = \frac{q}{4}[/tex]
Now, after the charges are separated with charge [tex]\frac{q}{4}[/tex] on each sphere B and C
Now,
When sphere A and Sphere C with charge [tex]\frac{q}{2}[/tex] and [tex]\frac{q}{4}[/tex] comes in contact with each other, conduction takes place and charge distribution is given as:
[tex]\frac{\frac{q}{2} + \frac{q}{4}}{2} = \frac{3q}{8}[/tex]