Answer:
[tex]t=5.84\times 10^{-5}s[/tex]
Explanation:
[tex]ln(\frac{A}{B})=-kt[/tex]
or, [tex]t=\frac{1}{-k}\times ln(\frac{A}{B})[/tex]
Now plug-in all given values:
[tex]t=\frac{1}{-4.80\times 10^{4}s^{-1}}\times ln(\frac{1.00\times 10M}{1.65\times 10^{2}M})[/tex]
So, [tex]t=5.84\times 10^{-5}s[/tex]