Respuesta :
Answer:
Part A : n = 1.77 moles
Part B : λ = [tex]2.01*10^{6} m^{-1}[/tex]
Part C : n = 0.154 moles
Explanation:
Part A
The problem gives you the equation for molarity M:
[tex]M=\frac{n}{V}[/tex]
n is the number of moles of solute and V is the volume
Then the problem gives you the molarity of a substance [tex]M=2.73\frac{mol}{L}[/tex] and the volume V = 0.650L, so you need to solve the equation for n:
[tex]M=\frac{n}{V}[/tex]
as the V is dividing it passes to multiply the M:
n = M*V
and you should replace the values:
[tex]n = 2.73\frac{mol}{L}*0.650L[/tex]
n = 1.77 moles
Part B
This time you have to solve the equation E = hcλ for λ that is the unknown information, so you have:
E = hcλ
h and c are multiplying so they pass to divide the E:
λ = [tex]\frac{E}{hc}[/tex]
and replacing the values:
λ = [tex]\frac{3.98*10^{-19}J}{(6.626*10^{-34}J.s)(2.99*10^{8}\frac{m}{s})}[/tex]
λ = [tex]2.01*10^{6} m^{-1}[/tex]
PartC
In this part the problem gives you the equation PV=nRT and the first thing you should do is to verify that all the quantities are in consistent units so:
[tex]R=8.206*10^{-2} \frac{L.atm}{K.mol}[/tex] so you need to convert the pressure to atmospheres and convert the volume to liters.
- Convert the pressure to atmospheres:
[tex]P=899torr*\frac{0.00131579atm}{1torr}[/tex]
P = 1.18 atm
- Convert the volume to liters:
[tex]V=3280mL*\frac{1L}{1000mL}[/tex]
V = 3.28L
To find the number of moles n, you should solve the equation for n:
Pv = nRT
As R and T are multiplying the n, they pass to divide to the other side of the equation:
[tex]n=\frac{PV}{RT}[/tex]
And finally you should replace the values:
[tex]n=\frac{(1.18atm)(3.28L)}{(8.206*10^{-2}\frac{L.atm}{K.mol})(307K)}[/tex]
n = 0.154 moles