Answer:197.504 N
Explanation:
Given
Two Charges with magnitude Q experience a force of 12.344 N
at distance r
and we know Electrostatic force is given
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
[tex]F=\frac{kQ\cdot Q}{r^2}[/tex]
[tex]F=\frac{kQ^2}{r^2}[/tex]
Now the magnitude of charge is 2Q and is at a distance of [tex]\frac{r}{2}[/tex]
[tex]F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}[/tex]
F'=16F
F'=197.504 N
