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What charge does a parallel plate capacitor having plates of area 1.4 m^2 that are separated by 0.04 mm of neoprene rubber hold when 9.00 V is applied to it? Give answer in terms of 10^-5 C. (Assume that neoprene has a dielectric constant of 6.7 or a dielectric strength of 12×10^6 V/m)

Respuesta :

Answer:

1.86 75 X 10⁻⁵ C.

Explanation:

Capacitance of parallel plate capacitor is given by

C = K∈₀ A /d

C is capacitance , A is plate area , d is distance between plate and ∈₀ is permittivity of air which is 8.85 x 10⁻¹²  and K is dielectric constant

Using the data given in the question

C = [tex]\frac{6.7\times 8.85\times10^{-12}\times 1.4}{.04\times10^{-3}}[/tex]

C = .2075 X 10⁻⁵ F

Charge Q = CV

.2075 X 10⁻⁵ X 9 = 1.86 75 X 10⁻⁵ C.