Answer:
The refractive index of the sphere is 2.66
Solution:
The refractive index, [tex]n_{w} = 1.33[/tex] and since the sphere is surrounded by water.
Therefore, according to the question, the parallel rays that affect one of the faces of the sphere converges on the second vortex:
Thus the image distance from the pole of surface 1, v' = 2R
where
R = Radius of the sphere
Now, using the eqn:
[tex]\frac{n_{w}}{v} + \frac{n}{v'} = \frac{n - n_{w}}{R}[/tex]
[tex]0 + \frac{n}{2R} = \frac{n - 1.33}{R}[/tex]
Since, v is taken as infinite
n = 2.66