Answer:
[tex]Q=3.47\times 10^{-15}\ C[/tex]
Explanation:
Given that,
Number of extra electrons, n = 21749
We need to find the net charge on the metal ball. Let Q is the net charge.
We know that the charge on an electron is [tex]q=1.6\times 10^{-19}\ C[/tex]
To find the net charge if there are n number of extra electrons is :
Q = n × q
[tex]Q=21749\times 1.6\times 10^{-19}\ C[/tex]
[tex]Q=3.47\times 10^{-15}\ C[/tex]
So, the net charge on the metal ball is [tex]3.47\times 10^{-15}\ C[/tex]. Hence, this is the required solution.
