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For a motor purchased for a tank project, it claims that at 12V it produces 6000 RPM. This motor is attached to a 50:1 gear reduction gearbox. The output of this gearbox is attached to a 2.5" wheel. Determine the speed of the tank under these conditions in miles/hour (mph).

Respuesta :

Answer:

0.889 mph

Explanation:

Given:

Voltage = 12 V

RPM produced, N₁ = 6000

Gear reduction gearbox, G = 50:1

Diameter of the wheel = 2.5" = 2.5 × 0.0254 = 0.0635 m

Now,

The output speed = [tex]\frac{N_1}{\textup{G}}=\frac{6000}{50}[/tex]  = 120 RPM

Thus,

The speed, v = [tex]\frac{\pi DN_2}{60}[/tex]

on substituting the respective values, we get

v = [tex]\frac{\pi\times0.0635\times120}{60}[/tex]  

or

v = 0.39878 m/s

Also,

1 m/s =  2.23 mph

thus,

v = 0.39878 × 2.23 = 0.889 mph

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