Answer:
Height, H = 25.04 meters
Explanation:
Initially the ball is at rest, u = 0
Time taken to fall to the ground, t = 2.261 s
Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :
[tex]H=ut+\dfrac{1}{2}at^2[/tex]
Here, a = g
[tex]H=\dfrac{1}{2}gt^2[/tex]
[tex]H=\dfrac{1}{2}\times 9.8\times (2.261)^2[/tex]
H = 25.04 meters
So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.
