Answer:
The car is traveling at [tex]8.1366\frac{m}{s}[/tex]
Explanation:
The known variables are the following:
[tex]V_{0} = 56 \frac{km}{h} = 15.56 \frac{m}{s}\\ D=25m\\ t=2.11s\\ V_{f}=?[/tex]
First, from the equation of motion we find the deceleration:
[tex]D=V_{0}*t+\frac{1}{2} a*t^{2} \\ a=\frac{2(D-V_{0})}{t^{2} } \\ a=3.5182\frac{m}{s^2}[/tex]
Then, with the equation for the speed:
[tex]V_{f}=V_{o}+a*t\\ V_{f}=8.1366\frac{m}{s}[/tex]
