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In fruit flies, bar eye is inherited by an X-linked allele (B for bar). If a heterozygous bar-eyed female is mated to a non-bar-eyed male, what will be the expected ratio of phenotype given four offspring?

Respuesta :

Answer:

barred eye vs non -barred  eye

[tex]2:2\\1:1[/tex]

Explanation:

Let the genotype of heterozygous bar-eyed female be [tex]X_BX_b[/tex]

where  [tex]X_B[/tex] represents the allele for X -linked dominant bar trait

while [tex]X_b[/tex] represents the allele for X -linked recessive trait

So the cross is carried out between [tex]X_BX_b[/tex] and [tex]X_bY[/tex]

The offspring produced are -

[tex]X_BX_b[/tex]

[tex]X_BY[/tex]

[tex]X_bX_b[/tex]

[tex]X_bY[/tex]

Phenotypic ration is

barred eye vs non -barred  eye

[tex]2:2\\1:1[/tex]

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