Answer:
Step-by-step explanation:
Given that a statistics student would like to estimate the average age of students at her college.
Population std dev =2.5years
For 99% , Z critical = ±2.59
Margin of error = [tex]±2.59*\frac{2.5}{\sqrt{n} } \\= \frac{±6.475}{\sqrt{n} } =0.5[/tex]
Simplify to get
[tex]\sqrt{n} =12.95[/tex]
n = 167.70
n=168
She must survey 168 people