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The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast: A + B → C + D slow A + C → E + F fast What is the net chemical equation predicted by this mechanism? A. A + B + C → D + E + F B. A + C → E + F C. A + B → C + D D. 2A + B → D + E + F E. A + B → D + E + F

Respuesta :

Answer: The correct answer is D.

Explanation:

We are given two reactions which are the two steps of a mechanism:

[tex]A+B\xrightarrow[]{slow}C+D[/tex]       ......(1)

[tex]A+C\xrightarrow[]{fast}E+F[/tex]        .......(2)

To determine the net chemical equation, we will simply add the above two equations, we get:

[tex]A+B+A+\not{C}\rightarrow \not{C}+D+E+F[/tex]

[tex]2A+B\rightarrow D+E+F[/tex]

The rate of the reaction depends on the slow step of the mechanism, which is:

[tex]Rate=k[A][B][/tex]

Thus, the correct answer is Option D.

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