Answer:
prob= 0.326
Step-by-step explanation:
Given that IQ scores (X) are normal (100, 15)
n = sample size =30
If we do not know population std deviation we can use t critical values with df =29
Std error of sample = [tex]\frac{15}{\sqrt{30} } \\=2.7387[/tex]
Thus we have sample mean is having mean = 100 and std dev = 2.7387
Mean falls within 1 std dev means mean lies in the interval
=100±2.7387
=(97.2613, 102.7387)
Prob t lies between -1 and 1 is 0.326