Answer:
Five pencils and two marches are worth greater than thirty paper clips.
Step-by-step explanation:
Let 'x' be paper clip.
Let 'y' be a match
and let 'z' be a pencil.
Now, let's write each statement as an equation:
Each paper clip can be traded for three matches:
x = 3y
Each pencil can be traded for six paper clips:
z = 6x
Now, five pencils equals 30 paper clips and two matches equals two thirds papel clips.
Therefore, we can say that Five pencils and two matches equals 30.66 matches. Therefore, five pencils and two marches are worth greater than thirty paper clips.
Answer:
less than
Step-by-step explanation:
Let x be the worth of a match.
Each paper clip can be traded for three matches. It means the worth of a paper clip is 3 times of the worth of a match.
Worth of a paper = 3x
Each pencil can be traded for six paper clips. It means the worth of a pencil is 6 times of the worth of a paper clip.
Worth of a pencil = 6(3x) =18x
The worth of a match, a paper and pencil are x, 3x and 18x respectively.
Worth of Twelve matches = 12 × x = 12x
Worth of two pencils and one paper clip = 2(18x) + 1(3x) = 39x
It is clear that
[tex]12x<39x[/tex]
because,
[tex]12<39[/tex]
Therefore, the twelve matches are worth less than two pencils and one paper clip.
