Answer:
a. the maximum number of σ bonds that the atom can form is 4
b. the maximum number of p-p bonds that the atom can form is 2
Explanation:
Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one s, 3 p and 2 d orbitals. In hybridization the number of hybrid orbitals generated is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.
The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.
This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.
And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.
Answer : The maximum number of σ bonds that the atom can form is 6.
The maximum number of p-p bonds that the atom can form is 0.
Explanation :
As we are given that the hybridization is [tex]sp^3d^2[/tex].
Bond pair = 6
Lone pair = 0
The number of electron density around the central atom is 6.
That means these molecule have central atoms with 0 lone pair and 6 atoms bond pair. Thus, the electronic geometry or molecular geometry of the molecule will be octahedral. For example : [tex]SF_6[/tex]
The maximum number of σ bonds that the atom can form is 6.
The maximum number of p-p bonds that the atom can form is 0.
