Answer:
[tex]\frac{dB}{dt} = 7.33 \times 10^{-3} T/s[/tex]
Explanation:
As we know that the changing magnetic field will induce the electric field in the plane perpendicular to the magnetic field
As per Faraday's law the induced EMF is given as
[tex]EMF = \frac{d\phi}{dt}[/tex]
[tex]EMF = \pi r^2 \frac{dB}{dt}[/tex]
now we also know that induced EMF is given as
[tex]EMF = \int E.dr[/tex]
[tex]EMF = E.(2\pi r)[/tex]
now we know that
[tex]E(2\pi r) = \pi r^2\frac{dB}{dt}[/tex]
[tex]E = \frac{r}{2}(\frac{dB}{dt})[/tex]
so we have
[tex]5.5 \times 10^{-3} = \frac{1.5}{2}(\frac{dB}{dt})[/tex]
[tex]\frac{dB}{dt} = 7.33 \times 10^{-3} T/s[/tex]