Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength 1.5 m from the center of the circle is 5.5 mV/m.

Respuesta :

Answer:

[tex]\frac{dB}{dt} = 7.33 \times 10^{-3} T/s[/tex]

Explanation:

As we know that the changing magnetic field will induce the electric field in the plane perpendicular to the magnetic field

As per Faraday's law the induced EMF is given as

[tex]EMF = \frac{d\phi}{dt}[/tex]

[tex]EMF = \pi r^2 \frac{dB}{dt}[/tex]

now we also know that induced EMF is given as

[tex]EMF = \int E.dr[/tex]

[tex]EMF = E.(2\pi r)[/tex]

now we know that

[tex]E(2\pi r) = \pi r^2\frac{dB}{dt}[/tex]

[tex]E = \frac{r}{2}(\frac{dB}{dt})[/tex]

so we have

[tex]5.5 \times 10^{-3} = \frac{1.5}{2}(\frac{dB}{dt})[/tex]

[tex]\frac{dB}{dt} = 7.33 \times 10^{-3} T/s[/tex]