Respuesta :
Answer:
a) 483,118.07 gallons of water is required to fill the pool.
b)1,828,800 kg is the mass of water in the pool.
Explanation:
Length of the Olympic-size pool,l = 50.0 m
Breadth of the Olympic-size pool,b = 25.0 m
Height up to which pool is to be filled,h = 4.8 feet = 1.46304 m
1 foot = 0.3048 m
Volume of the water in the pool = Volume of swimming pool
Volume of swimming pool = l × b × h
[tex]=50.0 m\times 25.0 m\times 1.46304 m=1828.8 m^3[/tex]
[tex] 1 m^3=10^6 cm^3=10^6 mL[/tex]
[tex]1828.8 m^3=10^6\times 1828.8 mL=1.8288\times 10^9 mL[/tex]
1 gal = 3785.41 mL
[tex]1.8288\times 10^9 mL=1.8288\times 10^9\times \frac{1}{ 3785.41} gal =483,118.07 gal[/tex]
b)Volume of the water in the swimming pool = [tex]1828.8 \times 10^9 mL[/tex]
Mass of water = m
Density of water = 1.0 g/mL
[tex]Density=\frac{Mass}{Volume}[/tex]
[tex]Mass=1.0 g/mL\times 1.8288\times 10^9 mL=1.8288\times 10^9 g[/tex]
1 kg = 1000 g
[tex]1.8288\times 10^9 g=1.8288\times 10^6 kg=1,828,800 kg[/tex]
1,828,800 kg is the mass of water in the pool.
