Respuesta :
Answer:
a) Volume of vial= 9.626cm3
b) Mass of vial with water = 62.92 g
Explanation:
a) Mass of empty vial = 55.32 g
Mass of Vial + Hg = 185.56 g
Therefore,
[tex]mass\ of\ Hg = 185.56-55.32 = 130.24 g[/tex]
Density of Hg = 13.53 g/cm3
[tex]Volume\ of\ vial = Volume\ of\ Hg = \frac{Mass}{Density} \\\\= \frac{130.24g}{13.53g/cm3} = 9.626 cm3[/tex]
b) Volume of water = volume of vial = 9.626 cm3
Density of water = 0.997 g/cm3
[tex]Mass\ of\ water = Density*volume = 0.997g/cm3*9.626cm3=9.60 g\\\\Total\ Mass\ of\ vial = Empty\ vial + mass\ of\ water\\= 53.32+9.60= 62.92g[/tex]
(a) The volume of the vial is 9.63 cm³
(b) The vial would weigh 64.92 g when filled with water
Density, Mass & Volume
(a) From the question, we are to determine the volume of the vial
Since, the vial was filled with mercury
Volume of the vial = Volume of the mercury
Now, we will determine the volume of the mercury
Using the formula,
[tex]Volume = \frac{Mass}{Density}[/tex]
First, we will determine the mass of the mercury
Mass of mercury = Mass of (vial + mercury) - Mass of vial
Mass of mercury = 185.56 g - 55.32 g
Mass of mercury = 130.24 g
Therefore,
Volume of the mercury = [tex]\frac{130.24}{13.53}[/tex]
Volume of the mercury = 9.626 cm³
Volume of the mercury ≅ 9.63 cm³
Hence, the volume of the vial is 9.63 cm³
(b) To calculate how much the vial would weigh when filled with water
First, we will determine the mass of water that will fill the vial
Using the formula,
Mass = Density × Volume
Mass of water = 0.997 × 9.63
Mass of water = 9.597 g
Then,
Mass of vial when filled with water = Mass of the vial + Mass of water
Mass of the vial when filled with water = 55.32 g + 9.597 g
Mass of the vial when filled with water = 64.917 g
Mass of the vial when filled with water ≅ 64.92 g
Hence, the vial would weigh 64.92 g when filled with water
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