Answer:
A
Step-by-step explanation:
The area of the shaded segment
= area of sector OAB - area of ΔOAB
area of sector = area of circle × fraction of circle, that is
A = πr² × fraction of circle
= π × 6² × [tex]\frac{60}{360}[/tex]
= 36π × [tex]\frac{1}{6}[/tex] = 6π units²
Area of triangle = 0.5 × 6 × 6 × sin60° = 18 × [tex]\frac{\sqrt{3} }{2}[/tex] = 9[tex]\sqrt{3}[/tex] units²
Hence
area of shaded segment = 6π - 9[tex]\sqrt{3}[/tex] units² → A
